For the first time, the Las Vegas Summer League is holding a tournament. Each of the 22 teams played three preliminary games used for the purpose of seeding the tournament. The Cavaliers went 2-1 in those games and earned the 7th seed. From the league-
“The participating 22 teams have each completed three games since the summer classic tipped off on July 12. Based on the outcome of those games, the teams are seeded 1-22 for the single elimination tournament that culminates in a championship game on July 22. Each team will compete in at least two more contests; a minimum of one game in the single elimination tournament, and the other in a consolation game if the team loses a game on either July 17 or July 18.
Teams seeded 11-22 will compete on Wednesday, with the winners of those contests advancing in the tournament to play Thursday against teams seeded 1-10, who earned a first-round “bye.” Teams on losing Wednesday and Thursday will play on Friday. The single elimination tournament resumes on Saturday with a champion being crowned on July 22. Seeding for the tournament was determined by won-loss records. Ties were broken using quarter-points and then point differential to determine the seedings.”
Here are the seeds-
1. Golden State, 2. Chicago, 3. Phoenix, 4. D-League Select, 5. Charlotte, 6. Toronto, 7. Cleveland, 8. LA Lakers, 9. Milwaukee, 10. San Antonio, 11. New Orleans, 12. Washington, 13. Minnesota, 14. Atlanta, 15. New York, 16. Dallas, 17. LA Clippers, 18. Miami, 19. Portland, 20. Sacramento, 21. Memphis, 22. Denver
The top half of the league earned a first round bye, so the Cavaliers will play San Antonio on Thursday. If the Cavaliers win, they advance to play the winner of the Chicago vs Miami/New York match-up.
If they lose to San Antonio they will play a consolation game against the loser of Milwaukee vs the Lakers.